35=-10x^2+5

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Solution for 35=-10x^2+5 equation: 



35=-10x^2+5

We move all terms to the left:

35-(-10x^2+5)=0

We get rid of parentheses

10x^2-5+35=0

We add all the numbers together, and all the variables

10x^2+30=0

a = 10; b = 0; c = +30;
Δ = b2-4ac
Δ = 02-4·10·30
Δ = -1200
Delta is less than zero, so there is no solution for the equation

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